Question

5. Find the distance between the points P(-4, 7) and Q(2,-5).
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Answer 1

Step-by-step explanation:

Points P(7,5) and Q(2,5)

We know that the distance between two points

=(x2−x1)2+(y2−y1)2

Therefore,

PQ=(2−7)2+(5−5)2

PQ=(−5)2+(0)2

PQ=25

PQ=5 units

Hence, the distance between points P and Q is 5 Units