Question

5.
Find the greatest number which divides 203 and 434 leaving remainder 5 in each
case.
6.
7.
Find the greatest number which will divide 625 and 1433 leaving remainders 5
and 3 respectively.
The length, breadth and height of a room are 8.25 m, 6.75 m and 4.50 m
respectively. Determine the longest tape which can measure the three dimensions
of the room exactly.
8.
There are 312 mango bites, 260 eclairs and 156 coffee bites in a box. These are
to be put in packets so that each packet contains the same number of toffees.
Find the maximum number of toffees in each packet.


help me fast....​

Answer 1

Step-by-step explanation:

Heya Mate

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5.

Given that the numbers 203 and 434 leaving remainder 5 in each case respectively

The numbers that are exactly divisible are 203-5=198 and 434-5=429

$198 = 2 \times 3 \times 3 \times 11 \\ \\ 429 = 3 \times 11 \times 13$

HCF(198,429)=3×11

=33

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6.

IT REFER TO THE ATTACHMENT

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7.

l=8.25m

b=6.75m

h=4.50m

PERIMETER=2(l+b)

Of Bottom and Top

2(8.25+6.75)

2(15)

30m

Top =Bottom=30

Now face one and three

2(l+h)

2(8.25+4.50)

2(12.75)

25.50m

Now,face two and fourth

2(b+h)

2(6.75+4.50)

2(11.25)

22.50m

Now,totally edge length

2(22.50+25.50+30)

2(45+30)

2(75)

150m

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8.

Maximum number of toffee in each packet

HCF=(312,260,156)

Thus by prime factorisation Method

312=2×2×2×3×13

260=2×2×5×13

156=2×2×3×13

Thus,HCF=2×2×13

HCF=52

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Hope it helped

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