Question

5) find the HCF of following expressions
x2+2x, X2-4 and x2+3x+2​

Answer 1

Answer :

H.C.F. = (x + 2)

Solution :

Here ,

The given expressions are ;

x² + 2x

x² - 4

x² + 3x + 2

Firstly ,

Let's factorize the given expressions .

• x² + 2x

→ x² + 2x

→ x(x + 2)

• x² - 4

→ x² - 4

→ x² - 2²

→ (x + 2)(x - 2)

• x² + 3x + 2

→ x² + 2x + x + 2

→ x(x + 2) + (x + 2)

→ (x + 2)(x + 1)

Clearly ,

The only common factor of all the given three expression is (x + 2) .

Hence ,

H.C.F. = (x + 2) .