Question

5. Find the perimeter the rhombus,
the length of whose diagonals are
20 cm and 16 cm.​

Answer 1

16$\sqrt{41\\}$

Answer 2

Answer:

in rhombus ABCD

AC=20cm

BD=16cm

since diagonals of a rhombus bisect each other at right angles.

angle AOD=90°

OA=1/2AC=10cm

OD=1/2BD=8cm

now in∆AOD,

using Pythagoras theorem,

AB²=OA²+OD²

AB²=10²+8²

AB=√100+64

AB=√164

AB=4√41 cm

therefore,

perimeter of rhombus=4×side

=4×4√41

=16√41 cm