5.
Find the perpendicular distance between two parallel lines of a trapezium whose parallel sides are 30
cm and 24 cm, and area is 405 cm2
Answers
Answer :-
- The perpendicular distance between two parallel lines of a trapezium is 15cm.
Step-by-step explanation:
To Find :-
- The perpendicular distance between two parallel sides of trapezium
Solution:
Given that,
- The parallel sides of trapezium = 30cm and 24cm
- The area of trapezium = 405cm²
As we know that,
Area of trapezium = 1/2 × (sum of all parallel sides) × (distance between them),
Assumption: Let us assume The perpendicular distance between two parallel lines of a trapezium as "h"
=> 1/2 × (sum of all parallel sides) × (distance between them) = Area
=> 1/2 × ( 30 + 24 ) × h = 405
=> 1/2 × 54 × h = 405
=> 1 × 27 × h = 405
=> 27 × h = 405
=> h = 405/27
=> h = 15
Hence,
- The perpendicular distance between two parallel lines of a trapezium is 15cm.
Given :-
- Area of Trapezium = 405cm²
- First Parallel Side = 30cm
- Second Parallel Side = 24cm
To Find :-
- Distance between two parallel Sides of a trapezium.
Solution :-
❍ As we know that Area of Trapezium is given by [ Area of Trapezium = ½ × Height × Sum of Parallel Side ]
Putting the Values :
⟼⠀⠀Area = ½ × Height × ( Sum of Sides )
⟼⠀⠀405 = ½ × Height × ( 30 + 24 )
⟼⠀⠀405 × 2 = Height × ( 30 + 24 )
⟼⠀⠀810 = Height × ( 30 + 24 )
⟼⠀⠀810 = Height × 54
⟼⠀⠀810 / 54 = Height
⟼⠀⠀15cm = Height
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Verification :-
⟼⠀⠀Area = ½ × Height × ( Sum of Sides )
⟼⠀⠀Area = ½ × 15 × ( 30 + 24 )
⟼⠀⠀Area = ½ × 15 × 54
⟼⠀⠀Area = 15 × 27
⟼⠀⠀405 = 405
Hence Verified
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Thus, Distance between the two parallel Sides of a trapezium is 15cm
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