Math, asked by chhabirambopche1203, 6 months ago

5. Find the smallest number of three digits
which when divided by 16, 24 and 40
leaves a remainder of 6 in each case.

Answers

Answered by SIMnaN35

0

answer

248 is the smallest number which when divided by 16, 24 and 40 leaves the remainder, 8. R = 8 . Hope, I helped you. 248 is the answer.

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