Question

5. Find the value of k so that the pair of equations has infinitely many solutions:

(b) x + (k+1)y = 4 and (k+1)x + 9y = 5k+2​

Answer 1

Answer:

k°–3k–4 = 0 => k°–4k + k –4 = 0 k (k–4) + 1 (K–4) = 0 (k–4) (k+1) = 0 => k = 4, ... k = 4 Thus, the pair of equations will have infinite number of solutions for k = 4. ... with equation ap + by + c = 0 and equation ax + by + c2 = 0, we get a1 = C, b ... of equations has infinitely many solutions: x + (k+1)) = 5 and (k+1)× + 9y = (8k – 1).

Gurukul Books - 2020 - ‎Mathematics

Step-by-step explanation:

Answer 2

Answer:

1/k+1=k+1/9

9=(k+1)²

9=k²+1+2k

k²+2k-8=0

k²+4k-2k-8=0

k(k+4)-2(k+4)=0

(k+4)(k-2)=0

k= -4 or K=2