5. Find the value of x in the given figure,
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name each vertices, A,B and C, such that A= 4x+3
B=81° and C= 42°
Now draw another line D from B to the bottom such that ABD is a straight line.
Now, L DBC + CBA= 180 ( straight line)
L DBC= 180-81°= 99°
In ∆ DBC,
L DBC+L BCD+ L CDB= 180°
L CDB+ 99+ 42= 180
L CDB= 180-141= 39°
Let the upper line be AF
So, LCDB +LBAF= 180 ( alternate opposite)
39° +L BAF= 180
L BAF= 180-39= 141
And we know, LBAF (interior) + LBAF (exterior)
= 360
141+ (4x+3)= 360
4x+3= 360-141
4x= 319-3
x= 316/4 = 79
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