Question

5. Find the zeroes of the quadratic poly. x' +7x +12 and verify the relation
between the zeroes and its coefficients.​

Answer 1

☆Question :-

• Find the zeroes of the quadratic poly. x' +7x +12 and verify the relation between the zeroes and itscoefficients.

☆Answer :-

• zeroes of the quadratic polynomial = -3 and -4

☆Given :-

• Quadratic polynomial $\tt{ x}^{2} + 7x + 12$

☆To find :-

• Find the zeroes of the quadratic poly. x' +7x +12 and verify the relation between the zeroes and its coefficients.

☆Solution :-

$\large \: \: \: \: \: \: \: \: \: \: \: \underbrace { \underline{ \sf First \: we \: factorise \: the \: equation : - }}$

$\large \\ \implies\tt x^2+7x+12=0$

$\large\\ \implies\tt(x + 3)(x + 4) = 0$

$\large\\ \implies\tt x = - 3 \: and \: x = - 4$

Now we find the relationship between the zeroes and its coefficients ,

$\large \tt Sum \: of \: roots = - \dfrac {b}{a} = - \dfrac{7}{1} = - 7 = ( - 3) + ( - 4)$

$\large \\ \tt Product \: of \: zeros = \dfrac{c}{a} = \dfrac{12}{1} = 12 = (- 3) \times ( - 4)$

Hence solved !!