Question

5. Find three consecutive integers such that four times the sum of all three is 2 times the
product of the larger two.​

Answer 1

Step-by-step explanation:

Let x = 1st consecutive integer

x+1 = 2nd

x+2 = 3rd

.

4(x + x+1 + x+2) = 2(x+1)(x+2)

4(3x + 3) = 2(x^2+3x+2)

12x + 12 = 2x^2+6x+4

0 = 2x^2-6x-8

0 = x^2-3x-4

0 = (x-4)(x+1)

.

x = {4,-1}

.

Solution: 4,5,6