Question

5. Find two numbers such that one of them exceeds the other by 13 and their sum is 77. I will mark as brainliest..

Answer 1

Answer:

the no. is

32 and 45

Step-by-step explanation:

let the one no. be x

than other be x + 13

then,

x + x + 13 = 77

2x + 13 = 77

2x = 77 - 13

2x = 64

x = 64/2

x = 32

first no. = x = 32

second no. = x + 13 = 32 +13 = 45

hope it help u

thanks