Physics, asked by agrimakukreti, 10 months ago

5. For the first 10 km of a marathon, a runner averages a velocity that
has a magnitude of 15 km - For the next 15 km he averages
10 km h- while for the last 15 km he averages 5 km Construct a
position-time graph for the runner​

Answers

Answered by amitnrw
19

Answer:

Explanation:

For the first 10 km of a marathon, a runner averages a velocity that

has a magnitude of 15 km - For the next 15 km he averages

10 km h- while for the last 15 km he averages 5 km Construct a

position-time graph for the runner​

For the first 10 km -  averages  velocity = 15 km/hr

=> Time taken = 10/15 = 2/3 hr = 40 mins

For the next 15 km he averages  10 km/hr

=> Time Taken = 15/10 = 3/2 hr = 90 mins

=> 10 + 15 = 25 km  at  40 + 90 = 130 mins

for the last 15 km he averages 5 km/hr

=>  Time Taken = 15/5 = 3 hr = 180 mins

=> 25 + 15 = 40 km at 130 + 180 = 310 min

Time (min)   Position (km)

0                  0

40                10

130               25

310               400

Attachments:
Answered by bhavik14632A
0

Answer:

its answer is 1.33 ms-² thank you ok

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