5. For the first 10 km of a marathon, a runner averages a velocity that
has a magnitude of 15 km - For the next 15 km he averages
10 km h- while for the last 15 km he averages 5 km Construct a
position-time graph for the runner
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Answer:
Explanation:
For the first 10 km of a marathon, a runner averages a velocity that
has a magnitude of 15 km - For the next 15 km he averages
10 km h- while for the last 15 km he averages 5 km Construct a
position-time graph for the runner
For the first 10 km - averages velocity = 15 km/hr
=> Time taken = 10/15 = 2/3 hr = 40 mins
For the next 15 km he averages 10 km/hr
=> Time Taken = 15/10 = 3/2 hr = 90 mins
=> 10 + 15 = 25 km at 40 + 90 = 130 mins
for the last 15 km he averages 5 km/hr
=> Time Taken = 15/5 = 3 hr = 180 mins
=> 25 + 15 = 40 km at 130 + 180 = 310 min
Time (min) Position (km)
0 0
40 10
130 25
310 400
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Answer:
its answer is 1.33 ms-² thank you ok
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