5- For what value of R, -4 is a zero of polynomial x2 -x-(2k+2)
Answers
Answered by
4
Hey user !!
Here is your answer !!
☆_________________________________________☆
Put value of x as -4 in the equation
(-4)^2-(-4)-(2k+2)=0
16+4-2k-2=0
20-2-2k=0
18-2k=0
18=2k
k=18/2
k=9
Hope it is satisfactory :-)
☆__________________________________________☆
Here is your answer !!
☆_________________________________________☆
Put value of x as -4 in the equation
(-4)^2-(-4)-(2k+2)=0
16+4-2k-2=0
20-2-2k=0
18-2k=0
18=2k
k=18/2
k=9
Hope it is satisfactory :-)
☆__________________________________________☆
vast1:
Give me one more answer
say!
If alpha and beta are the zero of f (x)=x^2-3x-2,find a quadratic polynomial whose zeroes are 1/alpha+beta and 1/2beta+alpha
say!
What
Answer please
Answered by
4
Hey
Here is your answer,
To find the value of k, just substitute -4 in the place of x.
X^2 -x- (2k+2)=0
(-4)^2 -(-4) - (2k+2)=0
16+4-2k-2=0
20-2k-2=0
18-2k=0
-2k=-18
k=-18/-2
k=9.
Hope it helps you!
Here is your answer,
To find the value of k, just substitute -4 in the place of x.
X^2 -x- (2k+2)=0
(-4)^2 -(-4) - (2k+2)=0
16+4-2k-2=0
20-2k-2=0
18-2k=0
-2k=-18
k=-18/-2
k=9.
Hope it helps you!
Similar questions