Math, asked by jahanvi3c, 3 months ago

5. For what value(s) of k, the given quadratic equation 3kx2 - 6x + 1 = 0 has no real
roots?
1.

Answers

Answered by help123456789

0

Step-by-step explanation:

Solution. The given quadric equation is kx2 + 6x + 1 = 0, and roots are real and distinct. Then find the value of k. Therefore, the value of k < 9.

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