Question

5. For what value(s) of k, the given quadratic equation 3kx2 - 6x + 1 = 0 has no real
roots?
1.​

Answer 1

Step-by-step explanation:

Solution. The given quadric equation is kx2 + 6x + 1 = 0, and roots are real and distinct. Then find the value of k. Therefore, the value of k < 9.