Math, asked by manojseat90, 9 months ago

5.
Given that HCF (156, 78) = 78, LCM (156, 78) is
(A) 156
(B) 78
(C) 156 x 78
(D) 156 x 2​

Answers

Answered by Anonymous
17

Step-by-step explanation:

LCM = a * b / HCF

= 156 * 78 / 78 = 156

Answered by windyyork
10

Option (A) is correct.

Step-by-step explanation:

Since we have given that

a = 156

b = 78

HCF (156, 78) = 78

So, we need to find the LCM (156,78).

As we know that

HCF\times LCM=a\times b\\\\78\times LCM=156\times 78\\\\LCM=156

Hence, Option (A) is correct.

# learn more:

Given that HCF (156, 78) = 78, LCM (156, 78) is

(A) 156

(B) 78

(C) 156 x 78

(D) 156 x 2​

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