Math, asked by a00864230, 10 months ago

sinA(1+tanA) + cosA (1+cotA) = secA + cosecA​

Answers

Answered by knjroopa
0

Step-by-step explanation:

Given SinA(1+tanA) + cosA (1+cotA) = secA + cosecA

  • Given sin A (1 + tan A) + cos A(1 + cot A)
  •      = sin A (1 + sin A / cos A) + cos A (1 + cos A / sin A)
  •     = sin A / cos A (sin A  + cos A) + cos A / sin A (sin A + cos A)
  •    = (sin A + cos A) (sin A / cos A + cos A / sin A)
  •        =  (sin A + cos A)(sin^2 A + cos ^2 A / cos A sin A)
  •        = sin A + cos A ( 1 / cos A sin A)
  •     =   sin A/ cos A sin A  + cos A / cos A sin A
  •      = sec A + cosec A  (proved)

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https://brainly.in/question/147206

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