sinA(1+tanA) + cosA (1+cotA) = secA + cosecA
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Step-by-step explanation:
Given SinA(1+tanA) + cosA (1+cotA) = secA + cosecA
- Given sin A (1 + tan A) + cos A(1 + cot A)
- = sin A (1 + sin A / cos A) + cos A (1 + cos A / sin A)
- = sin A / cos A (sin A + cos A) + cos A / sin A (sin A + cos A)
- = (sin A + cos A) (sin A / cos A + cos A / sin A)
- = (sin A + cos A)(sin^2 A + cos ^2 A / cos A sin A)
- = sin A + cos A ( 1 / cos A sin A)
- = sin A/ cos A sin A + cos A / cos A sin A
- = sec A + cosec A (proved)
Reference link will be
https://brainly.in/question/147206
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