Question

5. How would you prepare 250 mL of a 0.25 M solution of sodium carbonate using the sodium carbonate soln.​

Answer 1

Answer:

Prepare a 0.2-M solution of anhydrous sodium carbonate (2.2 g/100 mL).

Prepare a 0.2-M solution of sodium bicarbonate (1.68 g/100 mL).

Combine 4 mL of carbonate solution from Step 1 and 46 mL of bicarbonate solution from Step 2.

Bring to 200 mL with H2O. Final pH will be 9.2.