Question

5) (i) A bus starting from rest accelerates in a straight line at a constant rate of 3 m/ for

8 sec.

Calculate the distance travelled by the bus during this time interval.​

Answer 1

Answer:

96 metres

Explanation:

Given:

• Initial velocity = u = 0 m/s
• Time taken = t = 8 seconds
• Acceleration = a = 3 m/s²

To find:

Distance travelled by the bus during this period with the above acceleration

Using the second equation of motion which says: s=ut+1/2 at²

s=0×8+1/2×3×64

s=0+96

s=96

The distane travelled by the bus is equal to 96 metres

Extra:

first equation of motion = V=u+at

Third equation of motion = v²-u²=2as

Speed = distance/time

distance = speed×time

Time = distance / speed

Acceleration = (final velocity - initial velocity)/time

Answer 2

GIVEN:

• Initial Velocity (u) = 0 [bus start from rest]
• Acceleration (a) = 3 m/s²
• Time taken (t) by the bus = 8 sec

TO FIND:

• What is the distance travelled by the bus ?

SOLUTION:

Let the distance travelled by the bus be 's' m

To find the distance travelled by the bus, we use the second Equation of motion:-

⠀⠀ ❰ s = ut + $\bf{\dfrac{1}{2}}$ at²❱

According to question:-

On putting the given values in the equation, we get

➱ s = 0 $\times$ 8 + $\sf{\dfrac{1}{2}}$ $\times$ 3 $\times$ (8)²

➱ s = 0 + $\sf{\dfrac{1}{2}}$ $\times$ 3 $\times$ 64

➱ s = 3 $\times$ 32

❮ s = 96 m ❯

❝ Hence, the distance travelled by the bus is 96 m ❞

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