5.
Identify the oxidising agent and reducing agent in the following chemical equations.
(i) Pb2O4 + 8HCI → 3PbCl2 + Cl2 + 4H,0
(ii) 3Fe + 4H,0 → Fe2O4 + 4H,
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Answer:
pb2o4 is a reducing agent and cl2 is a oxidising agent
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oxidising agent reducing agent
i.Pb2O4 i.HCl
ii.H,O ii.Fe
hope this helps u
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