Question

5} If 2^a = 3^b = 6^c then show that c= ab/a+b
​

Answer 1

Answer:

2

a

=3

b

=6

c

alog2=blog3=clog6=K(say)

∴C=

log6

K

and log2=

a

K

and log3=

b

K

∴C=

log2+log3

K

=

K/a+K/b

K

∴C=

a+b

ab