5) If 4 tan theta = 3, (4 sin theta-cos theta) = (4 sin theta+cos theta)=
a. 2/3
b. 1/3
c. 1/2
d. 3/4
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Given 4Tanθ=3⇒Tanθ= 3/4
sinθ=3/5 cosθ=4/5
4sinθ-cosθ 4[3/5]-4/5
_________ = ___________
4sinθ+cosθ 4[3/5]+4/5
8/5
___
16/5
[after canceling]= 1/2
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