Question

5. If 6 oil tankers can be filled by a pipe in 4 and half hours, how long does the pipe take to fill 4 such oil tankers?​

Answer 1

Given :-

• 6 oil tankers can be filled by a pipe in 4½ hours.

To Find :-

• How long does the pipe take to fill 4 such oil tankers?

Used Formula :-

$\bf \red{⟼ \: Product \: of \: Means \: = \: Product \: of \: extremes}$

Solution :-

Given :

★ 6 oil tankers can be filled by a pipe in 4½ hrs.

Convert hrs into mins :

1hr = 60mins

4½hrs = ?

By Cross Multiplication :

$\displaystyle \bf \implies\: \frac{4\times 60}{1} = \: \frac{240}{1} =240mins$

$\displaystyle \bf \implies\: 240mins \: + 30mins = \red{270mins}$

According to the question :

★ 6 oil tankers can be filled by a pipe in 270mins.

So,

The pipe take to fill 4 such oil tankers are :

$⇢ \: \bf6 \: oil \: tankers \: = \: 270mins \\ \bf ⇢ \: 4 \: oil \: tankers \: = \: \: \: ? \:$

We know that,

$\bf \red{⟼ \: Product \: of \: Means \: = \: Product \: of \: extremes}$

Let,

$⇝ \: \: \bf6 \: oil \: tankers \: : \: 270mins \: : \: : \: 4 \: oil \: tankers \: : \: \: \: xmins \: \:$

$⟹ \: \: \sf6 \: : \: 270 \: : \: : \: 4 \: : \: \: \: ? \: \:$

$⟹ \: \: \sf6 \: \times \: x = \: 270 \times 4$

$⟹ \: \: \sf6 \: \times \: x = \:1080$

$\displaystyle⟹ \: \: \sf \: x = \: \cancel\frac{1080}{6}$

$\displaystyle⟹ \: \: \sf \: x = \: \frac{180}{1}$

$\displaystyle \red{⟹ \: \: \bf \: x = 180}$

We got,

➠ 180mins

We can also write it as 3hrs .

Hence,

∴ ❝ 4 oil tankers can be filled by a pipe in 3 hours. ❞

$\:$

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Answer 2

According to the question,

6 oil tankers can be filled by a pipe =4

2

1

=

2

9

hours

1 oil tanker can be filled by a pipe =

2×6

9

hours

4 oil tankers can be filled by a pipe

=

2×6

9

×4

=

6

9

×2

=

6

18

=3 hours

Hence, this is the answer.