Question

5.
If a, ß are zeroes of x2 + 7x + 7, find the value of a-' + ß-! - 2aß.​

Answer 1

a+ß= -7

a×ß= 7

Therefore,

a^(-1) + ß^(-1) - 2aß

=> 1/a + 1/ß - 2aß

=> (a+ß)/aß - 2aß.

=> -7/7 - 2×7

=> -1-14

=> -15