5. If a, b are the roots of 2x2 - 3x -5 = 0, form a equation whose roots are a2 and
b2 .
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a and b are the roots of 2x² - 3x - 5 = 0
sum of roots = - coefficient of x/coefficient of x²
a + b = -(-3)/2 = 3/2
product of roots = constant/coefficient of x²
ab = -5/2
Now, if roots of any equation has a² and b²
Then, a² + b² =(a + b)² - 2ab
= (3/2)² - 2(-5/2)
= 9/4 + 5
= 29/4
And a²b² = (ab)² = (-5/2) = 25/4
Now, equation is x² - (a² + b²)x + a²b² = 0
⇒ x² - (29/4)x + 25/4 = 0
⇒ 4x² - 29x + 25 = 0
Hence, required equation is 4x² - 29x + 25 = 0
sum of roots = - coefficient of x/coefficient of x²
a + b = -(-3)/2 = 3/2
product of roots = constant/coefficient of x²
ab = -5/2
Now, if roots of any equation has a² and b²
Then, a² + b² =(a + b)² - 2ab
= (3/2)² - 2(-5/2)
= 9/4 + 5
= 29/4
And a²b² = (ab)² = (-5/2) = 25/4
Now, equation is x² - (a² + b²)x + a²b² = 0
⇒ x² - (29/4)x + 25/4 = 0
⇒ 4x² - 29x + 25 = 0
Hence, required equation is 4x² - 29x + 25 = 0
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0
Answer:
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