6. If a, b are the roots of x2 -3x +2 = 0, form a quadratic equation whose roots are -a and -b.
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Answered by
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In the attachment I have answered this problem.
When the roots are given, the quadratic equation is found by
using following formula.
X^2 - [ sum òf roots] X + [ Product of
roots] = 0
I hope this answer helps you
When the roots are given, the quadratic equation is found by
using following formula.
X^2 - [ sum òf roots] X + [ Product of
roots] = 0
I hope this answer helps you
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Answered by
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a and b are tbe roots of x² - 3x + 2 = 0
sum of roots = - coefficient of x/coefficient of x²
a + b = - (-3)/1 = 3
product of roots = constant/coefficient of x²
ab = 2/1 = 2
Now, we have to find out equation whose roots - a and -b
We know, equation is written as
x² - (sum of roots)x + product of roots=0
so,sum of roots =-a - b = -(a + b) = -3
product of roots =(-a)(-b) = ab =2
Now, equation is x² - (-3)x + 2 =x² + 3x + 2
sum of roots = - coefficient of x/coefficient of x²
a + b = - (-3)/1 = 3
product of roots = constant/coefficient of x²
ab = 2/1 = 2
Now, we have to find out equation whose roots - a and -b
We know, equation is written as
x² - (sum of roots)x + product of roots=0
so,sum of roots =-a - b = -(a + b) = -3
product of roots =(-a)(-b) = ab =2
Now, equation is x² - (-3)x + 2 =x² + 3x + 2
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