Question

5. If centre of circle is at (-1,3) and one end of a diameter has coordinates (2,5), then find the
coordinates of the other end of diameter.​

Answer 1

Answer:

B= (-4, 1)

Step-by-step explanation:

Let,

the centre of the circle be and the diameter be seg AB.

Let,

O(-1,3) = (x,y)

A(2,5) = (x1 , y1)

B = (x2, y2)

OA = OB ------- radius of the circle

:. By midpoint formula,

x= x1 + x2 / 2 , y = y1 + y2 / 2

-1 = 2 + x2 /2 , 3 = 5 + y2 / 2

-2= 2 + x2 , 6 = 5 + y2

-2 - 2 = x2 , 6-5 = y2

:. x2 = -4 and y2 = 1

Ans--:. Coordinates of point B are (-4 , 1)

Answer 2

Answer:

B = (- 4, 1)

Step-by-step explanation:

Let,

the centre of the circle be and the diameter

be seg AB.

Let,

O(- 1, 3) = (x, y)

A(2,5) = (x1, y1)

B = = (x2, y2)

OA = OB

radius of the circle

:. By midpoint formula,

x= x1 + x2 / 2, y = y1+ y2/2

-1 = 2 + x2 /2, 3=5+ y2/2

-2= 2 + x2,6 = 5 + y2

-2 -2 = x2, 6-5 = y2

:. x2 = -4 and y2 = 1

Ans--:. Coordinates of point B are (-4,1)

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