Math, asked by rehanzaidi1218, 8 months ago

5. If m=-2 and n = 2; find the value of :
(1) m2 + n2 - 2mn
(ii) mp + nm
(iii) 6m-3 + 4n2
(iv) 2n3 – 3m
Exponents (Including Laws of Exponents)​

Answers

Answered by AngelicSmiles
81

{\huge{\sf{\underline{\underline{Solution}}}}}

\:\:\:{\sf{given:m\:=\:-2\:and:n\:=\:2}}

{\sf{m{^2}+n{^2}-2mn}}

\:\:\:{\sf{(-2) {^2}+2{^2}-2×-2×2}}

\:\:{\sf{4+4+8}}

{\sf{\boxed{\boxed{Answer=>16}}}}

{\sf{mn+nm}}

\:\:{\sf{-2×2+2(-2) }}

\:\:{\sf{-4-4}}

{\sf{\boxed{\boxed{Answer=>-8}}}}

{\sf{6m-3+4n{^2}}}

\:\:{\sf{6(-2) -3+4×2{^2}}}

\:\:{\sf{-12-3+4×4}}

\:\:{\sf{-15+16}}

{\sf{\boxed{\boxed{Answer=>1}}}}

{\sf{2n{^3}-3m}}

\:\:{\sf{2(2) {^3}-3(-2) }}

\:\:{\sf{2×8+6}}

\:\:{\sf{16+6}}

{\sf{\boxed{\boxed{Answer=>22}}}}

Answered by nobita76
2

Answer:

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Step-by-step explanation:

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