Question

5 If one zew of a polynomial (a²+9)x² +13x+6a is reciprocal of the other find the value of a.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let the one zero is alpha , then the second zero is 1/alpha .

alpha + 1/alpha = -13/(a²+9)

alpha * 1/alpha = 6a/(a²+9)

1 = 6a / (a²+9)

a² + 9 = 6a

a² - 6a + 9 = 0

(a - 3)² = 0

a - 3 = 0

a = 3