5 If one zew of a polynomial (a²+9)x² +13x+6a is reciprocal of the other find the value of a.
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Step-by-step explanation:
Let the one zero is alpha , then the second zero is 1/alpha .
alpha + 1/alpha = -13/(a²+9)
alpha * 1/alpha = 6a/(a²+9)
1 = 6a / (a²+9)
a² + 9 = 6a
a² - 6a + 9 = 0
(a - 3)² = 0
a - 3 = 0
a = 3
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