Question

5.If sin⁡θ=1/3,then find the value of :2cot^2 θ+2

18
1/3
9

guys please give the answer fast because I to clear it​

Answer 1

sin = 1/3. (given) .....(1)

2cot^2+2 =?

take 2common

2(cot^2+1)

by using formula: [cot^2+1=cosec^2]

2(cosec^2)

we know sin=1/cosec

2(1/sin^2)

put the value of sin

2×1÷(1/3)^2

2×9

=18

answer=18