Question

5.
If the energy difference between the ground state of
an atom and excited state is 4.4 x 10-19 J. The
wave length of photon required to produce this
transition is
(2) 4.5 x 10-7 nm
(1) 4.5 x 10-7 m
(3) 4.5 x 10-7 Å
(4) 4.5 * 10-7 cm​

Answer 1

Delta E=hc/lamda

Therefore 4.4*10^-7=6.62*10^-34*3*10^8/lamda=4.5 ×10^19