Question

5. If the first term of an AP is -5 and the common difference is 2
then the sum of first 6 terms is
​

Answer 1

Answer:

Step-by-step explanation:

Given, d = -2 , a = 5

Sum of first n terms of AP, Sₙ = n/2(2a + (n - 1)d)

                                                 = 6/2[2 * 5 + (6 - 1)(-2)]

                                                 = 3 (10 - 10)

                                                 = 0.

Answer 2

Answer:

$a(first \: term) = - 5 \\ d(common \: difference) = 2$

Terms of AP = -5, -3, -1, 1, 3, 5

Sum of first six terms of AP = -5+(-3)+(-1)+1+3+5=0[/tex]

Hope this helps!

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