Question

5. If the length of a rectangle is 15 cm more than its width and the perimeter is 150 cm,
find the dimensions of the rectangle.
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Answer 1

Answer:

ATQ

l= b + 15

perimeter

2(l+b)

2[(b+15)+b]= 150

2(2b+15)=150

2b+15= 75

2b = 75-15

2b = 60

b= 30

for l

l = b+15

l= 30+15

l= 45

Answer 2

Step-by-step explanation:

let the width of rectangle=x

so, length of rectangle = x+15

perimeter of rectangle=2(length+width)

2(x+x+15)=150

2(2x)+15=150

4x+30=150

4x=150-30

4x=120

x=120/4

x=30

so, width=40cm

length =40+15=55cm