Question

5) If the percentage
and mass
significant figures.
percentage error of measurement in velocity
2% and 4% respectively, what is the
percentage error in kinetic energy (k. E= 1/2 mv²)​

Answer 1

Answer:

8%

Explanation:

Given percentage errors in mass and velocity = 2% and 3% respectively

The kinetic energy of the particle is given by

KE =

2

mv

2

The percentage error in kinetic energy will be

m

Δm

×100+2

v

Δv

×100

= 2+6

= 8%

Answer 2

Explanation:

Given percentage errors in mass and velocity = 2% and 3% respectively

The kinetic energy of the particle is given by 

KE = 2mv2

The percentage error in kinetic energy will be

mΔm×100+2vΔv×100

= 2+6

= 8%