Question

5) If the sum of the zeroes of the quadratic polynomial 3x² - kx + 6 is 3, then find the value
of K.​

Answer 1

Step-by-step explanation:

$3 {x}^{2} - kx + 6 = 3$

Here , a=3

b=k

c=6

$b {}^{2} - 4ac = {k}^{2} - 4 \times 3 \times 6$

$= k {}^{2} - 72$

As per the question ,

$k { }^{2} - 72 = 3$

$k {}^{2} = 3 + 72$

$k {}^{2} = 75$

$k = \sqrt{75}$