5. If three unbiased coins are tossed, what is the probability of getting at most two heads?
1 point
(a) 3/4
Answers
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Step-by-step explanation:
Total no of probabilities= 2^3 =8
for 2/1/0 heads probability is =7(only 1 left HHH)
So we cannot include HHH, because it contains 3 heads.
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E)= n(S)/n(E)
= 8/7
Answer D
8/7
not 3/4 ok
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