The mean of eight numbers is 40. If one number
is excluded, their mean becomes 30. The ex-
cluded number is
0 30
130
0 110
0 138
Answers
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Therefore the value of the excluded term is 110. ( Option-c )
Given:
The mean of 8 numbers = 40
If one number is excluded, then their mean becomes 30.
To Find:
The excluded number.
Solution:
The given question can be solved as shown below.
Let the 8 numbers be x₁, x₂, ...., x₈
Mean = ( Sum of terms ) / ( Number of terms )
Given that,
The mean of 8 numbers = 40
⇒ ( x₁ + x₂ + .... + x₈ )/8 = 40
⇒ Then the sum of 8 terms = ( x₁ + x₂ + .... + x₈ ) = 8×40 = 320 (i.)
If one number is excluded, then their mean becomes 30.
Let us assume that, x₈ is excluded.
⇒ Then new mean = ( x₁ + x₂ + .... + x₇ )/7 = 30
⇒ Then the sum of 7 terms = ( x₁ + x₂ + .... + x₇ ) = 7×30 = 210 (ii.)
Subtracting equation-(ii.) from the equation-(i.),
⇒ ( x₁ + x₂ + .... + x₈ ) - ( x₁ + x₂ + .... + x₇ ) = 320 - 210
⇒ x₈ = 110
Therefore the value of the excluded term is 110.
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