Question

5
If triangle ABC is right angled at C, then the value of sec (A+B) is
a) 0
b) 1
c)
d) not defined​

Answer 1

Answer: ∴sec(A+B)=sec90°=1.option(B).

Step-by-step explanation:

we know that in a right angle triangle has one angle measure 90°.and other two angles are acute angle.

according to question in a right triangle ABC ,90°at C.

since,∠A+∠B+∠C=180.

∠A+∠B+ 90=180

⇒∠A+∠B=90°.

Now,sec(A+B)=sec90°

=1.

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