Question

5.
If two zeroes of the polynomial P ( x ) = x + 2x2 - 9x -18 are 3 and - 3.
find other zero of the polynomial, P(x).​

Answer 1

Given zeroes = (x-3) (x+3)

So,

$x {}^{2} - (3) {}^{2}$

therefore,

$x {}^{2} - 9$

Now, dividing given p(x) by

$x {}^{2} - 9$

We get, x+2

hence, the other zero of p(x) is -2

by x+2=0

so,x = -2

Hope it helps!!!