Math, asked by sarikajyothi647, 18 days ago

5. If x=2-a and y = 2+a is a solution of the equation 3x - 2y +6 = 0. Find the value of a. Find two more solutions of the resultant equation.​

Answers

Answered by priteshsorte29
0

Answer :

Given : 3x - 2y + 6 = 0

x = 2 - a

y = 2+ a

To find : value of a

Solution :

3x - 2y + 6 = 0

3 ( 2 - a ) - 2 ( 2 + a ) + 6 = 0

6 - 3a - 4 - 2a + 6 = 0

- 3a - 2a = 4 - 6 - 6

- 5a = 4 - 12

- 5a = - 8

5a = 8

a = 8/5

Answer :. a = 8/5

Answered by prakulshrotriya
0

Answer:

a = 8/5

Two more solutions :

  1. x = 0 ; y = 3
  2. x = (-2) ; y = 0

Explanation:

1. Finding the value of 'a' .

x = 2-a & y = 2+a

Equation given : 3x - 2y + 6 = 0

On putting the values of 'x' & 'y'.

3(2-a) - 2(2+a) + 6 = 0

[ (3×2) + {3× (-a)} ] + [ {(-2)×2} + {(-2)×a} ] + 6 = 0

{6 + (-3a)} + {(-4) + (-2a)} + 6 = 0

Opening the brackets :

6 - 3a - 4 - 2a + 6 = 0

6 + 6 - 4 - 3a - 2a = 0

12 - 4 - 5a = 0

8 - 5a = 0

-5a = -8

a = -8/-5

a = 8/5 Ans.

2. Two solutions for " 3x - 2y + 6 = 0

( i ) x = 0 ; y = 3

On putting the values,

3(0) - 2(3) + 6

= 0 - 6 + 6

= (-6) + 6 = 0

L.H.S. = R.HS.

So, x = 0 ; y = 3 is a Solution.

( ii ) x = (-2) ; y = 0

On putting the values,

3(-2) - 2(0) + 6

= (-6) - 0 + 6

= (-6) + 6 = 0

L.H.S. = R.HS.

So, x = (-2) ; y = 0 is a Solution

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