Question

5. If x = (3 + 18), then find the value of (i) x2 + 2 (ii) x4 + 3 (iii) x3 + 2​

Answer 1

x = (3 + 18)

x = 21

$i) {x}^{2} + 2 \\ \\ = {21}^{2} + 2 \\ \\ = 441 + 2 \\ \\ = 443 \\ \\ \\ ii) {x}^{4} + 3 \\ \\ = 194,481 + 3 \\ \\ \\ = 194,484 \\ \\ \\ iiii) {x}^{3} + 2 \\ \\ = 9,261 + 2 \\ \\ = 9,263$

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Answer 2

$\huge{Solution}$

Given--->x=(3+18)=21

(i)

${x}^{2} + 2$

$441 + 2$

=443

(ii)

${x}^{4} + 3$

$194481 + 3$

=194484

(iii)

${x}^{3} + 2$

$9261 + 2$

=9263

$\huge\underline{Divya}$❤