Question

5. In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find:
(i) the length of the arc (ii) area of the sector formed by the arc
(iii) area of the segment formed by the corresponding chord
​

Answer 1

Answer:

40 cm^2

Step-by-step explanation:

(I))length of arc = 21 × 60 × π/180

= 7π radian

(ii) sector area = 60/360 * π *(21)^2

= 1/6 * 22/7 * 441 = 231cm^2

(iii) central angle = 60° so the triangle formed will be an equilateral. ∆

otherwise you can also find the length of chord AB = 2r sin A/2 =2×21× sin60/2

= 21 cm

area of ∆ AOB = √3/4 * (21)^2

= 441√3/4 = 191 cm^2 (approx.)

area of the segment

= area of the sector - area of the ∆ AOB

= 231 - 191 = 40 cm^2

Answer 2

Answer:

hlo

Step-by-step explanation:

aao 3=4 wale question mai aao jalde

jalde aao baat karne hai