Question

The point which divides the line segment joining the points (8,-9) and (2,3) in
ratio 1 :2 internally lies in the
a) I quadrant
b) Il quadrant
c) IIl quadrant
d) IV quadrant​

Answer 1

Answer:

Option (d) IV Quadrant

Step-by-step explanation:

Given coordinates of point are

$(8,-9), (2,3)$

Let point P$(x,y)$ divides the given points in ratio $1:2$

Then, using the formula of internal division

$x=\frac{m_1x_2+m_2x_1}{m_1+m_2}$ and $y=\frac{m_1y_2+m_2y_1}{m_1+m_2}$

$x=\frac{1\times 2+2\times 8}{1+2}$

$\implies x=\frac{2+16}{3}$

$\implies x=\frac{18}{3}$

$\implies x=6$

And

$y=\frac{1\times 3+2\times (-9)}{1+2}$

$\implies y=\frac{3-18}{3}$

$\implies y=\frac{-15}{3}$

$\implies y=-5$

Therefore, the coordinate of point P is $(6,-5)$

Since the x-coordinate is positive and y-coordinate is negative

Therefore, the point lies in 4th quadrant

Hope this helps.

Answer 2

Answer:

(D) IV quadrant

hope it will be right