Math, asked by newareraju20, 11 months ago

5. In a game of chance, the spinning arrow rests at one of the
numbers 1, 2, 3, 4, 5, 6, 7, 8. All these are equally likely
outcomes. Find the probability of the following events.​

Answers

Answered by jagadhes1979
4

Answer:

the probability is 1/8

please mark it as a brainliest answer

Answered by aami1463
2

Answer:

  • We need to find the probability of the given events.

  • Now since, all of these outcomes are equally likely, the probability of the arrow to rest on any of the number = 1/8

Step by step explanation:

Now,

A) Let E be the event for arrow to be resting on an odd number.                                                           The possible outcomes are 1, 3, 5, 7.

So, P(E)= number of favorable outcomes/total number of outcomes

P(E)= 4/8 = 1/2

B) Let A be the event describing arrow resting on a prime number.                         The favorable outcomes are 2, 3, 5, 7.

So, P(A) = 4/8 = 1/2

C) Let B be the event describing arrow to rest on a multiple of 2.                                The favorable outcomes are 2, 4, 6, 8.

So, P(E) = 4/8 = 1/2.

So.then when we multiply 1/2×1/2×1/2

=1/8

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