Question

5. In Fig. 12.43, angleB=angleD = 90° and AB =DE. Prove that CD = BC.

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Answer 1

Step-by-step explanation:

In triangle ABC and triangle CDE,

Angle B = angle D (each 90°)

AB=DE (given)

angle ACB=Angle DCE (vertically opposite angles)

thus,

triangle ABC is congruent to triangle CDE (AAS criterion)

BC=CD (c. p. c. t)

Answer 2

triangle ABC congernt to CDE

A=Angle

A(B)=A(D) each 90⁰

AB=DE given

A(C)=A(C) (alternate inter Angeles)

BY CPCT,

CD=BC