5. In Fig. 6.32, if AB CD. APQ = 50° and
PRD=127°, find and y.
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Answered by
30
Step-by-step explanation:
by linear pair
interior angle R = 180 - 127 = 53°
since AB is parallel to CD
by parallel lines theorem
exterior angle at P = 53°
angle y = 180 - (53+50) = 77°
since sum of ∆PQR is 180 °
angle x = 180 - (53 + 77) = 50°
Answered by
4
Answer:
APQ = PQR (Alternate interior angles)
Now, putting the value of APQ = 50° and PQR = x we get,
x = 50°
Also,
APR = PRD (Alternate interior angles)
Or, APR = 127° (As it is given that PRD = 127°)
We know that
APR = APQ+QPR
Now, putting values of QPR = y and APR = 127° we get,
127° = 50°+ y
Or, y = 77°
Thus, the values of x and y are calculated as:
x = 50° and y = 77°
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