Question

5. In first case, a force of 5 N is applied on a object for

6 minutes and displaces it by 10 meters. In second

case, A force of 10 N is applied on the same object for

3 minutes and displaces it by 5 meters. In which case

there is more work done?

A) First case

B) Second case

C) In both cases, work done is same

D) In both cases, work done is zero​

Answer 1

Answer:

C) In both cases, work done is same

Answer 2

Answer:

C

Explanation:

Work done = F x displacement in direction of Force , so TIME plays no role in determining workdone.

in case 1 :  Work = 5 x 10 = 50 Joule

in case 2:  Work = 10x 5  = 50 Joule