Question

5 In space (no gravity), a stone is thrown with a velocity of (22 +63) m/s. Simultaneously, from the same point, a ball is thrown with a velocity of (2icap + 6jcap) m/s. What is the distance between the ball and the stone after 2 seconds?​

Answer 1

Answer:

While both the stones are in flight, a

1

=g and a

2

=g

So a

rel

=0⇒V

rel

=constant

⇒X

rel

=(const)t

⇒Curve ofx

rel

v/s t will be straight line.

After the first particle drops on ground, the seperation (x

rel

) will decrease parabolically (due to gravitational acceleration),

and finally becomes zero.

and V

rel

=slope of x

rel

v/st