Question

5. In the figure, AL is perpendicular to MB and AN is perpendicular to MC such that AL=AN. Show that MA bisects <BNC
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Answer 1

ANSWER

Here in ∆MLA and ∆MNA

< MLA= < MNA. (each 90°)

AM = AM ( Common)

AL= AN (Given)

Therefore ∆MLA is congurent to ∆MNA

: <AMN=<AML (cpct)

hence MA bisects <BNC