5. In the figure, LA = 120° then find ZC?
D
IC С
120
A
B В
Answers
Answered by
4
Answer:
ABCD is a cyclic quadrilateral. we have
∠ABC+∠ADC=180
o
∠ABC=180
o
−120
o
=60
o
Also ∠ACB=90
o
( angle on a semi circle )
In ΔABC we have
∠BAC+∠ACB+∠ABC=180
o
∠BAC+90
o
+60
o
=180
o
∠BAC=180
o
−150
o
=30
o
Similar questions