5. In the given circuit diagram, calculate:
192
A
392
w
B
C
312
212
ww
D
392
392
(i) Total resistance between the points B and E.
(ii) Total resistance between the points A and F.
229 Y while a 60 W lamp requires 0.272 A current at si
Answers
Given : A circuit
To Find :
(i) Total resistance between the points B and E.
(ii) Total resistance between the points A and F.
Solution:
Total resistance between the points B and E.
BC , CD , & DE are in series
Hence 1 + 2 + 3 = 6 Ω
BE through 3 Ω and through C & D 6 Ω are in parallel
Hence Total resistance between the points B and E.
= 1/( 1/3 + 1/6)
= 6/(2 + 1)
= 6/3
= 2 Ω
Total resistance between the points B and E.= 2 Ω
Total resistance between the points A and F.
= AB + BE + EF ( in series )
= 3 + 2 + 3
= 8 Ω
Total resistance between the points A and F. = 8 Ω
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